strmatch

• Reporter: vatiacg
• 소유자: (None)
• Type: Bugs
• Status: Closed
• Component: Tera Term Macro
• MileStone: (None)
• Priority: 5 - Medium
• Severity: 5 - Medium
• Resolution: Invalid
• File: None

Details Reply

Hello.

I would like to use strmatch to find '.' character in a string. strmatch '0 1.:23.:45.:67.:89.:a b' #46 But result will be always: 1

I tried '.' and #46 ASCII version too. With other characters it works and it tells the first position of the string what it founds.

I think it is a bug.

Best regards,

Tibor

Ticket History (3/3 Histories)

2023-03-08 02:08 Updated by: vatiacg

• New Ticket "strmatch" created

2023-03-08 07:27 Updated by: nmaya

댓글 올리기 Reply

Hi,

In Regular Expression, '.' matches any character.

cf. https://github.com/kkos/oniguruma/commit/9abbf54a3a12e3c637766813a6d58e71bc5a7cc5#diff-8a4fca15b4e397422096d6e0b219c3a97bf2f1efcb4485e12346c31cc0b33d8cL48

You have to escape it to match '.'.

strmatch '0 1.:23.:45.:67.:89.:a b' '.'
messagebox result 'not escape'

strmatch '0 1.:23.:45.:67.:89.:a b' '\.'
messagebox result 'escape'

2023-05-08 00:09 Updated by: nmaya

• Status Update from Open to Closed
• Resolution Update from None to Invalid